The length of a side of a rhombus is 5m and one of its diagonals is length 8m. The length of the other diagonal is
5m
7m
6m
8m
A
8m
B
6m
C
5m
D
7m
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Solution
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Diagonals of rhombus are cut each other at 90∘. Since d1=8 and a=5 Therefore, By Pythagoras theorem a2=(d12)2+(d22)2 52=42+(d22)2 ⇒(d22)2=25−16=9 ⇒d22=√9=3 ⇒d2=3×2=6
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