The wavelength of de broglie waves associated with a beam of protons of kinetic energy 5×102eV. (Mass of each photon=1.67×10−27Kg, h=6.62×10−34Js.)
2.42×10−12m
4.24×10−12m
1.82×10−12m
1.28×10−12m
A
4.24×10−12m
B
1.82×10−12m
C
1.28×10−12m
D
2.42×10−12m
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Solution
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12mv2=E
mv=√2Em
=√2×5×102×1.6×10−19×1.6×10−27
=51.69×1023N
λ=hmv
=6.62×10−3451.63×10−23
=1.28×10−12m
So, the answer is option (D).
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