Two radioactive sample A and B have half T1 and T2(T1>T2) respectively. At T=0, the activity of a B was twice the activity of A. Their activity will become equal after a time :
T1T2T1−T2
T1−T22
T1+T22
T1T212
A
T1T2T1−T2
B
T1−T22
C
T1+T22
D
T1T212
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Solution
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Consider initial activity of nuclei A and B be A0 and 2A0 respectively at a time ′t′ their activity is given by:-
A1A0e−λt [for A ] A2=2A0e−λt [for B]
where λ=ln2T [T=half -life]
When A1=A2 at time 't'
=A0e−ln2T1t=2A0e−ln2T2t [λ1=m2T1 and λ2=ln2T2]
Take log of both sides ,
−m2T1t=−m2T2+ln2
=−tT1=−tT2+1
=t=T1T2T1−T2
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