0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

100g is attached at the end of string of lenges 48.5 cm. Find angular velocity and tension the string, if bob is rotated now at 600 r.p.m. in horizontal circle (Neglect the weight of strin and bob). If the same bob is now whirled in vertical circle of same radius, what will be th difference in tensions at lowest and highes point ? Data: ) A spherical bob of diameter 3 em having a ma D = 3cm, R=5= 1.5 cm = 1.5×10-2 tt, 1 48.5 cm 48.5 x 10m r =R-1=48.5 x 10-2 + 1.5 × 10-2 50x 10m m = 100g=0.1kg n 600 r.p.m. 10 H, T-? ' w-? (For U.C.M.) Τι ? T2 ? (For Non U.CMl. Solut olution: Angular velocity ω=2×3.142 x 10 ω 62.84 rad/s = Tension in the string T=mro T = (0.1) (50 x 10-2) (62.84)- T = 197.4 N Difference in tensions at lowest and highe point T2-T1 = 6mg

Solution
Verified by Toppr





Was this answer helpful?
0
Similar Questions
Q1
The bob of a simple pendulum is given a velocity in horizontal direction when the bob is at lowest position ,so that the bob describes vertical circle of radius equal to length of pendulum and tension in the string is 10 N when the bob is at an angle 600 from lowest position of vertical circle. The tension in the string when the bob reaches highest position is (The mass of bob is 100 gram. g=10 ms2):
View Solution
Q2
The length of a simple pendulum is 50 cm and mass of its bob is 0.1 kg. The bob is given a velocity 5m/s along horizontal direction when the bob is at lowest position and the bob describes vertical circle of radius equal to length of pendulum. The position in the vertical circle, where the tension in the string is 4.5 N is (g=10ms2):
View Solution
Q3
A body of mass 0.1 kg attached at the end of a string 6 m long, is whirled in a vertical circle. The tension in the string is 6.4 N at the lowest point. What is the maximum angular velocity of the body? (g = 10 m/s2)
View Solution
Q4
One end of a string of length L and cross-sectional area A is fixed to a support and the other end is fixed to a bob of mass m. The bob is revolved in a horizontal circle of radius r with an angular velocity ω such that the string makes an angle θ with the vertical.
The tension T in the string is:
View Solution
Q5
A ring of radius R=50 cm having uniformly distributed charge Q=2 C is mounted in the middle of a rod suspended by two identical strings. The tension in strings in equilibrium is To=2 N. Now a vertical magnetic field is switched on, and the ring is rotated at constant angular velocity ω. Find the maximum ω with which the ring can be rotated if the strings can withstand a maximum tension of 3 N. (Take D=1 m and B=0.05 T)


View Solution