A ball of mass 0-5 kg is attached to the end of a string having length 0-5 m- The ball is rotated on a horizontal circular path about vertical axis- The maximum tension that the string can bear is 324 N- The maximum possible value of angular velocity of ball -in rad-s- is-9182736

Question

Toppr Admin · Accepted Answer

We have-Tsin-x3B8-mr-x3C9-2But-sin-x3B8-rL-x2234-T-mL-x3C9-2-x2234-324-0-5-xD7-0-5-xD7-x3C9-2-x2234-x3C9-36-xA0-rad-s

A ball of mass 0.5 kg is attached to the end of a string having length 0.5 m. The ball is rotated on a horizontal circular path about vertical axis. The maximum tension that the string can bear is 324 N. The maximum possible value of angular velocity of ball (in rad/s) is:9182736

We have,Tsinθ=mrω2But,sinθ=rL∴T=mLω2∴324=0.5×0.5×ω2∴ω=36 rad/s

We have,
$T s i n θ = m r ω^{2}$
But,
$s i n θ = \frac{r}{L}$
$∴ T = m L ω^{2}$
$∴ 324 = 0.5 \times 0.5 \times ω^{2}$
$∴ ω = 36 r a d / s$