A block of weight W is suspended from a spring balance. The lower surface of the block rests on a weighing machine. The spring balance reads $W_{1}$ and the weighing machine reads $W_{2}$ ( $W, W_{1}, W_{2}$ are in the same unit). Then :
$W = W_{1} + W_{2}$ if the system is at rest
$W > W_{1} + W_{2}$ if the system moves down with some acceleration
$W_{1} > W_{2}$ if the system moves up with some acceleration
no relation between $W_{1}$ and $W_{2}$ can be obtained with the given description of the system

Question

A block of weight W is suspended from a spring balance. The lower surface of the block rests on a weighing machine. The spring balance reads $W_{1}$ and the weighing machine reads $W_{2}$ ( $W, W_{1}, W_{2}$ are in the same unit). Then :
$W = W_{1} + W_{2}$ if the system is at rest
$W > W_{1} + W_{2}$ if the system moves down with some acceleration
$W_{1} > W_{2}$ if the system moves up with some acceleration
no relation between $W_{1}$ and $W_{2}$ can be obtained with the given description of the system

Toppr Admin · Accepted Answer

The system will remain rest if W-W1-W2As we know that acceleration will come due to the force - The system moves down if W-gt-W1-W2-Here the readings of the spring balance and the weighing machine are equal to the forces exerted by them on the body-

The system will remain rest if W=W1+W2As we know that acceleration will come due to the force . The system moves down if W>W1+W2.Here the readings of the spring balance and the weighing machine are equal to the forces exerted by them on the body.

The system will remain rest if $W = W_{1} + W_{2}$
As we know that acceleration will come due to the force .
The system moves down if $W > W_{1} + W_{2}$ .
Here the readings of the spring balance and the weighing machine are equal to the forces exerted by them on the body.