A body of mass 2 kg attached one end of light string is rotated along a vertical circle of radius 2 m- If the string can withstand a maximum tension of 140-6 N- the maximum speed with which the stone can be rotated is-22 m-s44 m-s33 m-s11 m-s

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Toppr Admin · Accepted Answer

M-2KgR-2mTmax-1406-xA0-NThe tension is max at bottom point-At bottom-xA0-T-x2212-mg-mv2R2-140-6-x2212-2X9-81-2-V2V-10-99-xA0-m-s

A body of mass $2 k g$ attached at one end of light string is rotated along a vertical circle of radius $2 m$ . If the string can withstand a maximum tension of $140.6 N$ , the maximum speed with which the stone can be rotated is:
$22 m / s$
$44 m / s$
$33 m / s$
$11 m / s$

$m = 2 K g R = 2 m$
$T_{m a x} = 1406 N$
The tension is max at bottom point.
At bottom:
$T - m g = \frac{m v^{2}}{R}$

$\frac{2 (140.6 - 2 X 9.81)}{2} = V^{2}$

$V = 10.99 m / s$

A body of mass 2 kg attached at one end of light string is rotated along a vertical circle of radius 2 m. If the string can withstand a maximum tension of 140.6 N, the maximum speed with which the stone can be rotated is:22 m/s44 m/s33 m/s11 m/s

m=2KgR=2mTmax=1406 NThe tension is max at bottom point.At bottom: T−mg=mv2R2(140.6−2X9.81)2=V2V=10.99 m/s

A body of mass $2 k g$ attached at one end of light string is rotated along a vertical circle of radius $2 m$ . If the string can withstand a maximum tension of $140.6 N$ , the maximum speed with which the stone can be rotated is:
$22 m / s$
$44 m / s$
$33 m / s$
$11 m / s$

$m = 2 K g R = 2 m$
$T_{m a x} = 1406 N$
The tension is max at bottom point.
At bottom:
$T - m g = \frac{m v^{2}}{R}$

$\frac{2 (140.6 - 2 X 9.81)}{2} = V^{2}$

$V = 10.99 m / s$