0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A person carries a hammer on his shoulder and holds the other end of its light handle in his hand. Let y be the distance between his hand and the point of support. If the person changes y, the pressure on his hand will be proportional to:
  1. y2
  2. 1y
  3. 1y2
  4. y

A
1y
B
y
C
y2
D
1y2
Solution
Verified by Toppr

As it is clear from the Free body diagram, for the hammer to be in equilibrium condition following should be followed :
F×y=w×(ly)
which gives;
F×y=w×lw×y
y=w×lF+w
F+ww×l=1y
Let w×l=d and 1l=c
Hence the new equation becomes;
Fd+c=1y
which gives F=dyc×d
Let c×d=a , which gives
F+a=dy
As "a" being a constant does not effect proportionality we have F inversely proportional to y.
96219_3177_ans_fbc7be8d896f4f3f94d5771df3e89b9c.png

Was this answer helpful?
0
Similar Questions
Q1
A person carries a hammer on his shoulder and holds the other end of its light handle in his hand. Let y be the distance between his hand and the point of support. If the person changes y, the pressure on his hand will be proportional to:
View Solution
Q2
If a person sitting on a rotating stool with his hands outstretched, suddenly lowers his hands, then his :
View Solution
Q3
If a person washes his hand and switches on the electric fan with wet hands. What might happen to him?
View Solution
Q4
A horizontal heavy uniform bar of weight 'W' is supported at its ends by two men. At the instant, one of the men lets go off his end of the rod, the other feels the force on his hand changed to

View Solution
Q5
When a person is unconscious, the doctor places his hand on his wrist and checks for:
View Solution