0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A uniform rod of length l is placed symmetrically on two walls as shown in figure. The rod is in equilibrium. If N1andN2 are the normal forces exerted by the walls on the rod then:
288562.JPG
  1. N1>N2
  2. N1<N2
  3. N1andN2 would be in the vertical directions
  4. N1=N2

A
N1andN2 would be in the vertical directions
B
N1<N2
C
N1=N2
D
N1>N2
Solution
Verified by Toppr

As the rod is in equilibrium, thus net torque about point O is zero i.e. τo=0
N1×l4N2×l4=0
N1=N2

572578_288562_ans.png

Was this answer helpful?
11
Similar Questions
Q1
A uniform rod of length l is placed symmetrically on two walls as shown in figure. The rod is in equilibrium. If N1 and N2 are the normal forces exerted by the walls on the rod then
1112346_47ed2871a09d43b6a1be312c59e601c6.png
View Solution
Q2
A uniform of rod of length l is placed symmetrically on two walls as shown in the figure. The rod is in equilibrium. If N1 and N2 are the normal forces exerted by the walls on the rod, then :
120010_4343ae2149fb4b10a4e4e39320e0916b.png
View Solution
Q3
A uniform rod of length 2l and mass m is suspended from one end by inextence string an other end lies on smooth ground. The angle made by rod with vertical is θ=sin1(1/3). If N1 and N2 represents the contact force from ground on rod just before and just after cutting string then find the ratio of N1/N2
1080223_416ff2121a1342d6bcd8a2ba0e9fa93c.png
View Solution
Q4
A sphere of mass m is kept between two inclined walls, as shown in the figure. All surfaces are smooth, then the ratio of normal reaction (N1/N2) offered by the walls 1 and 2 on the sphere will be:
1222028_d46bc096c3d24b9eaeb77865d8e96d0c.png
View Solution
Q5
N1 and N2 are the magnitudes of normal reactions in between the blocks kept on a smooth horizontal floor as shown in figures (a) and (b). The ratio N1N2 is


View Solution