A unifrom square plate 6m on a side has had a square piece 2m on side out of it - The centre of that piece is x-2m y-0 The center of the square plate is x-y-0-Find the x coordinate and y coordinate of the center of mass of the remaining piece-

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Toppr Admin · Accepted Answer

Xcom-x3C3-xD7-6-xD7-6-xD7-0-x2212-x3C3-xD7-2-xD7-2-xD7-2-x3C3-xD7-6-xD7-6-x2212-x3C3-xD7-2-xD7-2-x2212-8-32-x2212-0-25mYcom-x3C3-xD7-6-xD7-6-xD7-0-x2212-x3C3-xD7-2-xD7-2-xD7-0-x3C3-xD7-6-xD7-6-x2212-x3C3-xD7-2-xD7-2-0

A unifrom square plate $6$ m on a side has had a square piece $2$ m on side cut out of it . The centre of that piece is at $x = 2 m$ y= $0$ The center of the square plate is at x=y=0.Find the x coordinate and y coordinate of the center of mass of the remaining piece.

$X c o m = [(σ \times 6 \times 6) \times 0 - (σ \times 2 \times 2) \times 2] / (σ \times 6 \times 6) - (σ \times 2 \times 2) = - 8 / (32) = - 0.25 m$
$Y c o m = [(σ \times 6 \times 6) \times 0 - (σ \times 2 \times 2) \times 0] / (σ \times 6 \times 6) - (σ \times 2 \times 2) = 0$

A unifrom square plate 6m on a side has had a square piece 2m on side cut out of it . The centre of that piece is at x=2m y=0 The center of the square plate is at x=y=0.Find the x coordinate and y coordinate of the center of mass of the remaining piece.

Xcom=[(σ×6×6)×0−(σ×2×2)×2]/(σ×6×6)−(σ×2×2)=−8/(32)=−0.25mYcom=[(σ×6×6)×0−(σ×2×2)×0]/(σ×6×6)−(σ×2×2)=0

A unifrom square plate $6$ m on a side has had a square piece $2$ m on side cut out of it . The centre of that piece is at $x = 2 m$ y= $0$ The center of the square plate is at x=y=0.Find the x coordinate and y coordinate of the center of mass of the remaining piece.

$X c o m = [(σ \times 6 \times 6) \times 0 - (σ \times 2 \times 2) \times 2] / (σ \times 6 \times 6) - (σ \times 2 \times 2) = - 8 / (32) = - 0.25 m$
$Y c o m = [(σ \times 6 \times 6) \times 0 - (σ \times 2 \times 2) \times 0] / (σ \times 6 \times 6) - (σ \times 2 \times 2) = 0$