A water bucket of mass 'm' is revolved in a vertical circle with the help of a rope of length 'r'. If the velocity of the bucket at the lowest point is √7gr . Then the velocity and tension in the rope at the highest point are:
√3gr,2mg
√2gr,mg
√gr,mg
Zero , Zero
A
Zero , Zero
B
√3gr,2mg
C
√2gr,mg
D
√gr,mg
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Solution
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Vb=√7gr
Work Energy Theorem applied between top and bottom.
mg(2R)=12m(Vb)2−12m(VT)2
2mgr=72mgr−12m(VT)2
VT=√3gr
At top point:
T=mV2Tr−mg
=m3grr−mg
=2mg
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