An object is taken to height 2R above the surface of earth, the increase in potential energy is [R is radius of earth]
2 mgR
mgR2
mgR3
2mgR3
A
2mgR3
B
mgR2
C
mgR3
D
2 mgR
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Solution
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Change in gravitational potential energy at a height h above the earth's surface is △U=mgh1+(hr)
=mg.2R1+2RR [here,h=2R]
=2mgR3
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