Solve
Guides
Join / Login
Use app
Login
0
You visited us
0
times! Enjoying our articles?
Unlock Full Access!
Standard XII
Physics
Ideal Gas Equation
Question
At what temperature will the mean molecular energy of a perfect gas be one-third of its value of 27
o
C?
10
o
C
10
2
K
10
1
K
10
3
J
A
10
3
J
B
10
1
K
C
10
2
K
D
10
o
C
Open in App
Solution
Verified by Toppr
Mean
K
E
∝
T
therefore at T=27 which in kelvin becomes 300 K
So KE will be 1/3 when temperature becomes 1/3 which is 300/3=100K
option (C)
Was this answer helpful?
0
Similar Questions
Q1
At what temperature will the mean molecular energy of a perfect gas be one-third of its value of 27
o
C?
View Solution
Q2
At what temperature will the kinetic energy of gas molecules be double of its value at 27
o
C?
View Solution
Q3
The mean kinetic energy of a gas molecule at 27
o
C is 6.21
×
10
−
21
Joule. Its value at 227
o
C will be
View Solution
Q4
The temperature of a gas is increased from 27
o
C to 127
o
C. The ratio of its mean kinetic energies will be
View Solution
Q5
The temperature of gas is increased from 27
o
C to 127
o
C. The ratio of its mean kinetic energies will be
View Solution