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Question

Calculate the equilibrium constant at 25 degrees celsius given the Standard Free Energy value of - 107.2 kJ
  1. - 43.2
  2. 43.2
  3. 6.18 x 108
  4. 1.04
  5. 6.18 x 109

A
1.04
B
6.18 x 108
C
43.2
D
- 43.2
E
6.18 x 109
Solution
Verified by Toppr

The temperature is 25 deg C or 298 K
ΔG0=RTlnK
ΔG0=107.2kJ=107200J
107200=8.314×298×lnK
lnK=43.268
K=6.18×1018

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