If an alkane has number of carbon atoms equal to n, then the number of moles of oxygen required for its complete combustion is?
$\frac{3 n + 1}{2}$
$\frac{n}{2}$
$(2 n + 1)$
$2 n$

Question

If an alkane has number of carbon atoms equal to n- then the number of moles of oxygen required its complete combustion is-dfrac-3n-1-2-dfrac-n-2-2n-1-2n

Toppr Admin · Accepted Answer

CH4 -2O2 -x2192- CO2 -2H2OC2H6- 72O2 -x2192- 2CO2 -3H2OOn observing these two reactions we can make general formula for requirement of oxygen molecules-In general for an alkalane having -apos-n-apos- number of carbon atoms-xA0-no- of moles of oxygen required will be- 3n-12

If an alkane has number of carbon atoms equal to n, then the number of moles of oxygen required for its complete combustion is?3n+12n2(2n+1)2n

CH4 +2O2 → CO2 +2H2OC2H6+ 72O2 → 2CO2 +3H2OOn observing these two reactions we can make general formula for requirement of oxygen molecules.In general for an alkalane having 'n' number of carbon atoms no. of moles of oxygen required will be= 3n+12

If an alkane has number of carbon atoms equal to n, then the number of moles of oxygen required for its complete combustion is?
$\frac{3 n + 1}{2}$
$\frac{n}{2}$
$(2 n + 1)$
$2 n$