If uncertainty in momentum of an electron is $1\times 10^{-5}kgm{s}^{-1}$, then what will be uncertainty in position?

According to Heisenberg's equation:
$\Delta x\times \Delta p=\frac{h}{4\pi }$

where $\Delta x\&\Delta p$ are uncertainity in position and momentum of electron respectively

$⟹$ Uncertainity in position = $=6.63\times 10^{-34}/4\times 3.14\times (1\times 10^{-5})$ $=5.28\times 10^{-30}m$