If uncertainty in momentum of an electron is $$1\times 10^{-5}kg\ ms^{-1}$$, then what will be uncertainty in position?
According to Heisenberg's equation:
$$\Delta x\times \Delta p=\dfrac{h}{4\pi}$$
where $$\Delta x \ \& \ \Delta p$$ are uncertainity in position and momentum of electron respectively
$$\implies$$ Uncertainity in position = $$=6.63\times 10^{-34}/4\times 3.14\times (1\times 10^{-5})$$ $$=5.28\times 10^{-30}m$$