If uncertainty in momentum of an electron is $1 \times 1 0^{- 5} k g m s^{- 1}$ , then what will be uncertainty in position?

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Answer 1

According to Heisenberg's equation:
$Δ x \times Δ p = \frac{h}{4 π}$

where $Δ x & Δ p$ are uncertainity in position and momentum of electron respectively

$⟹$ Uncertainity in position = $= 6.63 \times 1 0^{- 34} / 4 \times 3.14 \times (1 \times 1 0^{- 5})$ $= 5.28 \times 1 0^{- 30} m$

Answer 2

According to Heisenberg's equation:

Δ x \times Δ p = \frac{h}{4 π}

where

Δ x & Δ p

are uncertainity in position and momentum of electron respectively

⟹

Uncertainity in position =

= 6.63 \times 1 0^{- 34} / 4 \times 3.14 \times (1 \times 1 0^{- 5})

= 5.28 \times 1 0^{- 30} m

If uncertainty in momentum of an electron is $1 \times 1 0^{- 5} k g m s^{- 1}$ , then what will be uncertainty in position?

Solution

According to Heisenberg's equation:
$Δ x \times Δ p = \frac{h}{4 π}$

where $Δ x & Δ p$ are uncertainity in position and momentum of electron respectively

$⟹$ Uncertainity in position = $= 6.63 \times 1 0^{- 34} / 4 \times 3.14 \times (1 \times 1 0^{- 5})$ $= 5.28 \times 1 0^{- 30} m$

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If the mass of electron is $9.11 \times 1 0^{- 31}$ kg. Planck's constant is $6.626 \times 1 0^{- 34}$ J-s and uncertainty in position is $0.1 A o$ , then uncertainty in velocity is?

The uncertainty in the momentum of an electron is $1 0^{- 6} k g m s^{- 1}$ . What will be the uncertainty in its position? [ $h = 6.6 \times - 1 0^{- 34} J s$ ]

The uncertainty in the momentum of an eklectron is $10 \times 1 0^{- 5} k g m s^{- 1}$ .The uncertainty in its position will be:
$(h = 6.62 \times 1 0^{- 34} k g m^{2} s^{- 1})$

The uncertainty in the momentum of an electron is $1.0 \times 1 0^{- 5} k g m s^{- 1}$ . The uncertainty in its position will be (h = $6.626 \times 1 0^{- 34}$ Js) :

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If uncertainty in momentum of an electron is 1×10−5kg ms−1, then what will be uncertainty in position?

According to Heisenberg's equation: Δx×Δp=4πh​ where Δx & Δp are uncertainity in position and momentum of electron respectively ⟹ Uncertainity in position = =6.63×10−34/4×3.14×(1×10−5) =5.28×10−30m

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If the mass of electron is 9.11×10−31 kg. Planck's constant is 6.626×10−34 J-s and uncertainty in position is 0.1Ao, then uncertainty in velocity is?

The uncertainty in the momentum of an electron is 10−6kgms−1. What will be the uncertainty in its position? [h=6.6×−10−34Js]

The uncertainty in the momentum of an eklectron is 10×10−5kgms−1.The uncertainty in its position will be: (h=6.62×10−34kgm2s−1)

The uncertainty in the momentum of an electron is 1.0×10−5kgms−1. The uncertainty in its position will be (h = 6.626×10−34 Js) :

Calculate the uncertainty in the momentum of an electron if it is confined to a linear region of length 1×10−10m.

More From Chapter

Structure of Atom

Shortcuts & Tips

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Practice more questions

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If uncertainty in momentum of an electron is $1 \times 1 0^{- 5} k g m s^{- 1}$ , then what will be uncertainty in position?

According to Heisenberg's equation:
$Δ x \times Δ p = \frac{h}{4 π}$

where $Δ x & Δ p$ are uncertainity in position and momentum of electron respectively

$⟹$ Uncertainity in position = $= 6.63 \times 1 0^{- 34} / 4 \times 3.14 \times (1 \times 1 0^{- 5})$ $= 5.28 \times 1 0^{- 30} m$

If the mass of electron is $9.11 \times 1 0^{- 31}$ kg. Planck's constant is $6.626 \times 1 0^{- 34}$ J-s and uncertainty in position is $0.1 A o$ , then uncertainty in velocity is?

The uncertainty in the momentum of an electron is $1 0^{- 6} k g m s^{- 1}$ . What will be the uncertainty in its position? [ $h = 6.6 \times - 1 0^{- 34} J s$ ]

The uncertainty in the momentum of an eklectron is $10 \times 1 0^{- 5} k g m s^{- 1}$ .The uncertainty in its position will be:
$(h = 6.62 \times 1 0^{- 34} k g m^{2} s^{- 1})$

The uncertainty in the momentum of an electron is $1.0 \times 1 0^{- 5} k g m s^{- 1}$ . The uncertainty in its position will be (h = $6.626 \times 1 0^{- 34}$ Js) :

Calculate the uncertainty in the momentum of an electron if it is confined to a linear region of length $1 \times 10^{- 10} m$ .