A bog of mass m - 50 gm is oscillating with the of a string- the maximum value of angle from the vertical attained by the bog is 60-o- -The tension in the string extreme position is

Question

A bog of mass  m - 50 gm is oscillating with the of a string- the maximum value of angle from the vertical attained by the bog is 60-o- -The tension in the string extreme position is

Toppr Admin · Accepted Answer

Correct option is A- 0-25 NIn the given problem at the extreme position- the tension in the-160-string and the weight mg balance each other-160-But weight mg is resolved into -mgcos-theta- and hence-T - mgcos-theta - -left-50 -times 10-3-right- -times -10- -times -frac-1-2-0-25 N-

A bog of mass $$ m = 50\ gm$$ is oscillating with the help of a string, the maximum value of angle from the vertical attained by the bog is $$60^{o}$$ .The tension in the string at extreme position is

Correct option is A. 0.25 N
In the given problem at the extreme position, the tension in the string and the weight mg balance each other.
But weight mg is resolved into $$mgcos\theta$$ and hence
$$T = mgcos\theta = \left(50 \times 10^{-3}\right) \times (10) \times \frac{1}{2}=0.25 N$$

A bog of mass $$ m = 50\ gm$$ is oscillating with the help of a string, the maximum value of angle from the vertical attained by the bog is $$60^{o}$$ .The tension in the string at extreme position is

Correct option is A. 0.25 NIn the given problem at the extreme position, the tension in the string and the weight mg balance each other. But weight mg is resolved into $$mgcos\theta$$ and hence$$T = mgcos\theta = \left(50 \times 10^{-3}\right) \times (10) \times \frac{1}{2}=0.25 N$$

Correct option is A. 0.25 N
In the given problem at the extreme position, the tension in the string and the weight mg balance each other.
But weight mg is resolved into $$mgcos\theta$$ and hence
$$T = mgcos\theta = \left(50 \times 10^{-3}\right) \times (10) \times \frac{1}{2}=0.25 N$$