In the molecule XeO2F2, there exists one n-fold axis of symmetry and in the molecule XeO2F4, the number of 2-fold axis of symmetry is m. The value of m+n is :
6
7
5
8
A
7
B
6
C
8
D
5
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Solution
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In XeO2F2, there exists one 2(n)-fold axis of symmetry, while in XeO2F4, there exists four (m)2-fold axis of symmetry. The structures are given in the figure. Hence, n=2 and m=4.
Therefore, n+m=2+4=6
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