Na-2O-2 is an oxide of alkali metal which is diamagnetic-If true enter 1- else enter 0-

Question

Toppr Admin · Accepted Answer

Concept-If a substance is having even number of electrons -or- no unpaired electrons in theirr molecular orbital diagram-it is said to be diamagnetic-Na2O2 consists of 11-2-8-2 equals to 38 electrons which is even number-so diamagneticHence option 1 is correct-

$N a_{2} O_{2}$ is an oxide of alkali metal which is diamagnetic.
If true enter 1, else enter 0.

Concept:If a substance is having even number of electrons (or) no unpaired electrons in theirr molecular orbital diagram,it is said to be diamagnetic.
$N a_{2} O_{2}$ consists of 112+82 equals to 38 electrons which is even number,so diamagnetic
Hence option 1 is correct.

Na2O2 is an oxide of alkali metal which is diamagnetic.If true enter 1, else enter 0.

Concept:If a substance is having even number of electrons (or) no unpaired electrons in theirr molecular orbital diagram,it is said to be diamagnetic.Na2O2 consists of 11*2+8*2 equals to 38 electrons which is even number,so diamagneticHence option 1 is correct.

$N a_{2} O_{2}$ is an oxide of alkali metal which is diamagnetic.
If true enter 1, else enter 0.

Concept:If a substance is having even number of electrons (or) no unpaired electrons in theirr molecular orbital diagram,it is said to be diamagnetic.
$N a_{2} O_{2}$ consists of 112+82 equals to 38 electrons which is even number,so diamagnetic
Hence option 1 is correct.