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Question
On the basis of the following $$ E^o $$ values, the strongest oxidizing agent is $$ [Fe(CN)_6]^{4-} \rightarrow [Fe(CN)_6]^{3-} +e^{-} ; E^o = -0.35 V $$ $$ Fe^{2+} \rightarrow Fe^{3+} +e^- ; E^o = -0.77V $$
A
$$ Fe^{3+} $$
B
$$ [Fe(CN)_6]^{3-} $$
C
$$ [Fe(CN)_6]^{4-} $$
D
$$ Fe^{2+} $$
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Solution
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Correct option is A. $$ Fe^{3+} $$
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Q1
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