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Question

The apparent weight of a person in a lift moving downwards is half his apparent weight in the same lift moving upwards with the same magnitude of acceleration. Acceleration of the lift is:
  1. g
  2. g/2
  3. g/3
  4. g/4

A
g/2
B
g/3
C
g
D
g/4
Solution
Verified by Toppr

Apparent weight of a person in lift will be m(g+a) while moving upwards whereas it will be m(ga) while moving downwards.

Hence, as per the given information,

m(g+a)=2m(ga)

g+a=2g2a

Hence, a=g3

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