The correct statements among (a) to (d) are:
(a) saline hydrides produce $$H_{2}$$ gas when reacted with $$H_{2}O$$.
(b) Reaction of $$LiAlH_{4}$$ with $$BF_{3}$$ leads to $$B_{2}H_{6}$$.
(c) $$PH_{3}$$ and $$CH_{4}$$ are electron - rich and electron - precise hydrides, respectively.
(d) $$HF$$ and $$CH_{4}$$ are called as molecular hydrides.
Correct option is C. (a), (b), (c) and (d)
(a) $$\underset {Ionic\ hydride/ saline\ hydride}{\overset {\oplus}{M} \overset {\ominus}{H} + HOH} \rightarrow MOH + H_{2}$$
(b) $$4BF_{3} + 3LiAlH_{4}\rightarrow 2B_{2}H_{6} + 3LiF + 3AlF_{3}$$
(C) Ref, image.
(d) $$HF$$ and $$CH_{4}$$ are molecular hydride because they are covalent molecules.