The equation $Δ x . Δ p \geq \frac{h}{4 π}$ shows :

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Answer 1

The equation $Δ x . Δ p \geq \frac{h}{4 π}$ shows Heisenberg's uncertainty principle. According to this principle, it is not possible to determine simultaneously the position and momentum of a moving microscopic particle (electron) with absolute accuracy.

Answer 2

The equation

Δ x . Δ p \geq \frac{h}{4 π}

shows Heisenberg's uncertainty principle. According to this principle, it is not possible to determine simultaneously the position and momentum of a moving microscopic particle (electron) with absolute accuracy.

The equation $Δ x . Δ p \geq \frac{h}{4 π}$ shows :

de-Broglie relation

Heisenberg's uncertainty principle

Aufbau principle

Hund's rule

The equation $Δ x . Δ p \geq \frac{h}{4 π}$ shows Heisenberg's uncertainty principle. According to this principle, it is not possible to determine simultaneously the position and momentum of a moving microscopic particle (electron) with absolute accuracy.

For an electron, if the uncertainty in velocity is $Δ V$ , the uncertainty in its position $(Δ X)$ is given by:

$Δ u_{x}$ is uncertainty in velocity of electron and $Δ x_{y}$ is uncertainty in position, then:

The uncertainties in the velocities of two particles, $A$ and $B$ are $0.05$ and $0.02$ $m s^{- 1}$ respectively. The mass of $B$ is five times to that of the mass of $A$ .
What is the ratio of uncertainties $\frac{Δ x _{A}}{Δ x _{B}}$ in their positions?

State True or False.

The $Δ p$ and $Δ x$ in Heisenberg parallel to $x$ -axis are restricted by the uncertainty principle.

Uncertainty in position of a hypothetical subatomic particle is 1 $A^{o}$ and uncertainty in velocity is $\frac{3 . 3}{4 π} \times 1 0^{5}$ m/s. Then the mass of the particle is approximately: $[h = 6.6 \times 1 0^{- 34} J s]$

Revise with Concepts

Developments Leading to Quantum Mechanical Model

Limitations of Bohr's Model

The equation Δx.Δp≥4πh​ shows :

de-Broglie relation

Heisenberg's uncertainty principle

Aufbau principle

Hund's rule

The equation Δx.Δp≥4πh​ shows Heisenberg's uncertainty principle. According to this principle, it is not possible to determine simultaneously the position and momentum of a moving microscopic particle (electron) with absolute accuracy.

For an electron, if the uncertainty in velocity is ΔV, the uncertainty in its position (ΔX) is given by:

Δux​ is uncertainty in velocity of electron and Δxy​ is uncertainty in position, then:

The uncertainties in the velocities of two particles, A and B are 0.05 and 0.02 ms−1 respectively. The mass of B is five times to that of the mass of A. What is the ratio of uncertainties ΔxB​ΔxA​​ in their positions?

State True or False. The Δp and Δx in Heisenberg parallel to x-axis are restricted by the uncertainty principle.

Uncertainty in position of a hypothetical subatomic particle is 1 Ao and uncertainty in velocity is 4π3.3​×105 m/s. Then the mass of the particle is approximately: [h=6.6×10−34Js]

Revise with Concepts

Developments Leading to Quantum Mechanical Model

Limitations of Bohr's Model

The equation $Δ x . Δ p \geq \frac{h}{4 π}$ shows :

The equation $Δ x . Δ p \geq \frac{h}{4 π}$ shows Heisenberg's uncertainty principle. According to this principle, it is not possible to determine simultaneously the position and momentum of a moving microscopic particle (electron) with absolute accuracy.

For an electron, if the uncertainty in velocity is $Δ V$ , the uncertainty in its position $(Δ X)$ is given by:

$Δ u_{x}$ is uncertainty in velocity of electron and $Δ x_{y}$ is uncertainty in position, then:

The uncertainties in the velocities of two particles, $A$ and $B$ are $0.05$ and $0.02$ $m s^{- 1}$ respectively. The mass of $B$ is five times to that of the mass of $A$ .
What is the ratio of uncertainties $\frac{Δ x _{A}}{Δ x _{B}}$ in their positions?

State True or False.

The $Δ p$ and $Δ x$ in Heisenberg parallel to $x$ -axis are restricted by the uncertainty principle.

Uncertainty in position of a hypothetical subatomic particle is 1 $A^{o}$ and uncertainty in velocity is $\frac{3 . 3}{4 π} \times 1 0^{5}$ m/s. Then the mass of the particle is approximately: $[h = 6.6 \times 1 0^{- 34} J s]$