The geometry and the number of unpaired electron(s) of $[M n B r_{4}]^{2 -}$ , respectively, are:
square planar and 1
square planar and 5
tetrahedral and 1
tetrahedral and 5

Question

The geometry and the number of unpaired electron-s- of -MnBr-4-2- respectively- are- square planar and 1square planar and 5tetrahedral and 1tetrahedral and 5

Toppr Admin · Accepted Answer

Mn2- have d5 configuration and as Br-x2212- is a weak field ligand it cannot pair up the d electrons therefore the hybridisation will be sp3 and the geometry will be tetrahedral with 5 unpaired electrons-

The geometry and the number of unpaired electron(s) of [MnBr4]2−, respectively, are: square planar and 1square planar and 5tetrahedral and 1tetrahedral and 5

Mn2+ have d5 configuration and as Br− is a weak field ligand it cannot pair up the d electrons therefore the hybridisation will be sp3 and the geometry will be tetrahedral with 5 unpaired electrons.

The geometry and the number of unpaired electron(s) of $[M n B r_{4}]^{2 -}$ , respectively, are:
square planar and 1
square planar and 5
tetrahedral and 1
tetrahedral and 5

$M n^{2 +}$ have $d^{5}$ configuration and as $B r^{-}$ is a weak field ligand it cannot pair up the d electrons therefore the hybridisation will be $s p^{3}$ and the geometry will be tetrahedral with 5 unpaired electrons.