Question

The hydride ion, $H^{-}$ is a stronger base than its hydroxide ion $O{H}^{-}$. Which of the following reactions will occur, if sodium hydride $\left(NaH\right)$ is dissolved in water?

• A. $H^{-}\left(aq\right)+H_{2}O\to H_{2}O$
• B. $H^{-}\left(aq\right)+H_{2}O\left(l\right)\to O{H}^{-}+H_2$
• C. $H^{-}+H_{2}O\to Noreaction$
• D. $Noneoftheabove$

Answer 1

Answer: (B)

Sodium hydride $\left(NaH\right)$ react with water to form hydrogen gas and the sodium hydroxide $\left(NaOH\right)$.
$NaH+H_{2}O\to H_2+NaOH$
i.e., $N{a}^{+},H^{-}$ and $H^{+},O{H}^{-}$ give rise to $H_2$ and $NaOH$. So, it is similar to option B.