The linear momentum P of a body varies with time and is given by the equation P=x+yt2 where x and y are constants. The net force acting on the body for a one-dimensional motion is proportional to:
1t
t
t2
aconstant
A
t2
B
aconstant
C
t
D
1t
Open in App
Solution
Verified by Toppr
P=x+yt2 F=dPdt=2yt∝t
Was this answer helpful?
7
Similar Questions
Q1
The linear momentum P of a body varies with time and is given by the equation P=x+yt2 where x and y are constants. The net force acting on the body for a one-dimensional motion is proportional to:
View Solution
Q2
The linear momentum `P’ of a moving body in one dimensional frame varies with time as P=x−yt2, where x and y are position constants. The rate of change of momentum is the force that acts on the body. In such a case the force is
View Solution
Q3
The linear momentum p of a body moving in one dimension varies with time t according to the equation p=a+bt2, where a and b are positive constants. The net force acting on the body is
View Solution
Q4
The components of the linear momentum of a body moving in the X-Y plane are given by Px=Asin(t) and Py=Acos(t), where ′A′ is a constant and ′t′ is time. The angle between the linear momentum and the force acting on the body is
View Solution
Q5
The linear momentum P of a particle varies with time as follow P=a+bt2. Where a and b are constants. The net force acting on the particle is: