The measurement of the electron position is associated with an uncertainty in momentum, which is equal to 1×10−18g cm s−1. The uncertainty in electron velocity is,(mass of an electron is 9×10−28g)
1×109 cm s−1
1×106 cm s−1
1×1011 cm s−1
1×105 cm s−1
A
1×109 cm s−1
B
1×106 cm s−1
C
1×1011 cm s−1
D
1×105 cm s−1
Open in App
Solution
Verified by Toppr
As per the Heisenberg's uncertainity principle equation,
momemtum is given by,
Δp=mΔv
Therefore, Δv=1×10−18gcms−19×10−28g
Δv=0.92×1010cm/s≈109cm/s
Was this answer helpful?
6
Similar Questions
Q1
The measurement of the electron position is associated with an uncertainty in momentum, which is equal to 1×10−18gcms−1.
The uncertainty in electron velocity is: (mass of an electron is 9×10−28g)
View Solution
Q2
The measurement of the electron position is associated with an uncertainty in momentum, which is equal to 1×10−18gcms−1. The uncertainty in electron velocity is (mass of an electron is 9×10−28g)
View Solution
Q3
The measurement of the position of the electron is associated with an uncertainty in momentum, which is equal to 1×10−18g cm s−1. The uncertainty in the velocity of the electron is:
(Mass of an electron is 9×10−28g)
View Solution
Q4
The measurement of the position of the electron is associated with an uncertainty in momentum, which is equal to 2.5×10−8g cm s−1. The uncertainty in the velocity of the electron is:
(Mass of an electron is 9×10−28g)
View Solution
Q5
If a 1.00 g body is travelling along X-axis at 100 cm s−1 with an uncertainty in velocity as 2 cm−1. Then uncertainty in its position is :