The moment P -in kg- ms-1- of a particle is varying with time t -in second- as p-2-3t-2- The force acting on the particle t-3s will be 18 N15 N54 N9 N

Question

Toppr Admin · Accepted Answer

Given-p-2-3t2From Newton-apos-s second law-F-dpdtF-d-2-3t2-dtF-0-6t-6tAt t-3sF-6-xD7-3-18NThe correct option is A-

The moment P (in $k g m s^{- 1}$ ) of a particle is varying with time t (in second) as $p = 2 + 3 t^{2}$ . The force acting on the particle at $t = 3 s$ will be
18 N
15 N
54 N
9 N

Given,
$p = 2 + 3 t^{2}$

From Newton's second law,
$F = \frac{d p}{d t}$

$F = \frac{d (2 + 3 t^{2})}{d t}$

$F = 0 + 6 t = 6 t$

At $t = 3 s$

$F = 6 \times 3 = 18 N$
The correct option is A.

The moment P (in kgms−1) of a particle is varying with time t (in second) as p=2+3t2. The force acting on the particle at t=3s will be 18 N15 N54 N9 N

Given,p=2+3t2From Newton's second law,F=dpdtF=d(2+3t2)dtF=0+6t=6tAt t=3sF=6×3=18NThe correct option is A.

The moment P (in $k g m s^{- 1}$ ) of a particle is varying with time t (in second) as $p = 2 + 3 t^{2}$ . The force acting on the particle at $t = 3 s$ will be
18 N
15 N
54 N
9 N

Given,
$p = 2 + 3 t^{2}$

From Newton's second law,
$F = \frac{d p}{d t}$

$F = \frac{d (2 + 3 t^{2})}{d t}$

$F = 0 + 6 t = 6 t$

At $t = 3 s$

$F = 6 \times 3 = 18 N$
The correct option is A.