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Standard XII
Mathematics
Negation
Question
The negation of the statement
(
p
→
q
)
∧
r
is
p
∧
∼
q
∨
∼
r
(
∼
p
∧
q
)
∧
(
∼
r
)
(
p
∧
∼
q
)
∧
(
r
)
(
p
∧
∼
q
)
∧
(
∼
r
)
A
p
∧
∼
q
∨
∼
r
B
(
p
∧
∼
q
)
∧
(
∼
r
)
C
(
p
∧
∼
q
)
∧
(
r
)
D
(
∼
p
∧
q
)
∧
(
∼
r
)
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Solution
Verified by Toppr
p
→
q
=
∼
p
∨
q
−
−
−
(
1
)
∼
[
(
p
→
q
)
∧
r
]
∼
[
∼
p
∨
q
∧
r
]
...[form(i)]
∼
(
∼
p
∨
q
)
∨
∼
r
...[Demorgans low]
∼
(
∼
p
)
∧
∼
q
∨
q
∼
r
a
v
(
b
∧
c
)
p
∧
∼
q
∨
∼
r
=
(
a
∨
b
)
∨
(
a
∨
c
)
]
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