The number of atoms of Cr and O are 4.8×1010 and 9.6×1010 respectively. Its empirical formula is?
Cr2O3
CrO2
Cr2O4
None of these
A
Cr2O3
B
CrO2
C
Cr2O4
D
None of these
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Solution
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Number of atoms of Cr = 4.8×1010
Number of atoms of O = 9.6×1010
The ratio of number of atoms of Cr to O = 4.8×10109.6×1010=1:2
Hence, empirical formula of the compound is CrO2
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