The number of electrons which will together weight one gram is :
$9.1096 \times 10^{31} e l e c t r o n s$
$1.098 \times 10^{27} e l e c t r o n s$
$1 e l e c t r o n$
$1 \times 10^{4} e l e c t r o n s$

Question

The number of electrons which will together weight one gram is -9-1096times 10-31- electrons1-098times 10-27- electrons1 electron1times 10-4- electrons

Toppr Admin · Accepted Answer

Mass of 1 electron -9-1-xD7-10-x2212-28-xA0-gLet n electrons have mass of 1-xA0-gthus- n-xD7-9-1-xD7-10-x2212-28-1n-1-099-xD7-1027 electronsoption A is correct

The number of electrons which will together weight one gram is :9.1096×1031electrons1.098×1027electrons1 electron1×104electrons

Mass of 1 electron =9.1×10−28 gLet n electrons have mass of 1 gthus, n×9.1×10−28=1n=1.099×1027 electronsoption A is correct

The number of electrons which will together weight one gram is :
$9.1096 \times 10^{31} e l e c t r o n s$
$1.098 \times 10^{27} e l e c t r o n s$
$1 e l e c t r o n$
$1 \times 10^{4} e l e c t r o n s$

Mass of 1 electron $= 9.1 \times 10^{- 28} g$
Let $n$ electrons have mass of $1 g$
thus, $n \times 9.1 \times 10^{- 28} = 1$
$n = 1.099 \times 10^{27}$ electrons
option A is correct