The number of radial nodes and angular nodes for d-orbital can be represented as:
(n-3) radial nodes + 2 angular node = (n-l-1) total nodes
(n-2) radial nodes + 1 angular node = (n-1) total nodes
(n-1) radial nodes + 1 angular node = (n-1) total nodes
(n-3) radial nodes + 2 angular node = (n-1) total nodes

Question

The number of radial nodes and angular nodes for d-orbital can be represented as:
(n-3) radial nodes + 2 angular node = (n-l-1) total nodes
(n-2) radial nodes + 1 angular node = (n-1) total nodes
(n-1) radial nodes + 1 angular node = (n-1) total nodes
(n-3) radial nodes + 2 angular node = (n-1) total nodes

Toppr Admin · Accepted Answer

Number of radial nodes -n-x2212-l-x2212-1Number of angular nodes -l-xA0-x2234-Total number of nodes -n-x2212-l-x2212-1-l-n-x2212-1For d-orbital- l-2-thus number of radial nodes -n-x2212-2-x2212-1-n-x2212-3and number of angular nodes -l-2Total nodes-n-x2212-1

Number of radial nodes =n−l−1Number of angular nodes =l ∴Total number of nodes =n−l−1+l=n−1For d-orbital, l=2,thus number of radial nodes =n−2−1=n−3and number of angular nodes =l=2Total nodes=n−1

Number of radial nodes $= n - l - 1$
Number of angular nodes $= l$
$∴$ Total number of nodes $= n - l - 1 + l = n - 1$
For d-orbital, $l = 2$ ,
thus number of radial nodes $= n - 2 - 1 = n - 3$
and number of angular nodes $= l = 2$
Total nodes $= n - 1$