The overall charge is zero (because it is not an ion). Since sodium is a 1A family member, the charge is +1. The charge of oxygen is almost always -2. Hence, 1+OSofN+(3×−2)=0 So, the oxidation of nitrogen in that problem is +5.
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Similar Questions
Q1
The oxidation state of nitrogen in NaNO3 is :
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Q2
Suggest a list of the substances where carbon can exhibit oxidation states from –4 to +4 and nitrogen from –3 to +5.
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Q3
The oxidation number of nitrogen atoms in NH4NO3 are:
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Q4
Oxidation states of P in H4P2O6,H4P2O6,H4P2O7 are respectively:
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Q5
What is the oxidation number of both the nitrogen atoms in NH4NO3 ?