Solve
Guides
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The terminals of a battery of e.m.f. 12$$\mathrm { V } $$ and internal resistance 1$$ \Omega $$ are connected to a circular coil of resistance 16$$ \Omega $$ at two points distant a quarter of the circumference of the coil. The current flowing through the smaller arc of the circle is

A
2.4 A
B
2.25 A
C
0.75 A
D
0.5 A
Open in App
Solution
Verified by Toppr

Correct option is A. 2.4 A

Was this answer helpful?
1
Similar Questions
Q1
terminals of 18 V battery with internal resistance 24 ohm are connected to circular wire of resistance 24 ohm at two points distant at one quarter of circumference of circular wire , current through bigger arc of circle is 0.75 A 1.5 A 2.25 A 3 A
View Solution
Q2
The terminals of a 18V battery with an internal resistance of 1.5Ω are connected to a circular wire of resistance 24Ω at two points distant at one quarter of the circumference of a circular wire. The current through the bigger arc of the circle will be
View Solution
Q3
The terminals of a 18V battery with an internal resistance of 24 ohms are connected to a circular wire of resistance 24 ohms at two points distant at one quarter of the circumference of a circular wire . The current through the bigger arc of the circle will be (a)2.25A (b)3A (c)0.75A (d) 1.5A
View Solution
Q4
A series combination of two resistors 1 Ω each is connected to a 12 V battery of internal resistance of 0.4 Ω . The current flowing through it is
View Solution
Q5
A circular loop has a resistance of $$40 \Omega$$. Two points P and Q of the loop, which are one-quarter of the circumference apart are connected to a 24 V battery, having an internal resistance of $$0.5 \Omega$$. What is the current flowing through the battery?
View Solution