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Question

The uncertainty in position of particle of 25gm in space is 10.5×105 m. Hence, uncertainty in velocity ms1 is:
  1. 2.1×1028
  2. 0.5×1034
  3. 2.1×1034
  4. 5.0×1024

A
2.1×1034
B
2.1×1028
C
0.5×1034
D
5.0×1024
Solution
Verified by Toppr

Expression for Heisenberg's uncertainty principle is written as, Δv.Δx=h4πm.

Where Δv and Δx are uncertainty in velocity and position respectively.

Δv=h4πm.Δx=6.62×10344×π×25×103×10.5×105=2.1×1028.

Hence, option A is correct.

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