Total how many atoms are present in the formula Ca3(PO4)2?
8
9
12
5
13
A
5
B
9
C
13
D
8
E
12
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Solution
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Following atoms are present in the given formula:
Ca = 3 atoms P = 2 atoms O = (4×2) 8 atoms
Total number of atoms present in the formula = 3 + 2 + 8 = 13.
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