Two persons P and Q of the same height are carrying a uniform beam of length 3 m- If Q is one end- then the distance of P from the other end such that P- Q receive loads in the ratio 5 - 3 is-0-5 m0-6 m0-75 m1 m

Question

Toppr Admin · Accepted Answer

NP-NQ-Mgalso NPNQ-53-x21D2-NP-58Mg-NQ-38Mg

Two persons $P$ and $Q$ of the same height are carrying a uniform beam of length $3 m$ . If $Q$ is at one end, then the distance of $P$ from the other end such that $P$ , $Q$ receive loads in the ratio $5 : 3$ is:
$0.5 m$
$0.6 m$
$0.75 m$
$1 m$

$N_{P} + N_{Q} = M g$
also $\frac{N_{P}}{N_{Q}} = \frac{5}{3}$
$\Rightarrow N_{P} = \frac{5}{8} M g; N_{Q} = \frac{3}{8} M g$

Two persons P and Q of the same height are carrying a uniform beam of length 3m. If Q is at one end, then the distance of P from the other end such that P, Q receive loads in the ratio 5:3 is:0.5 m0.6 m0.75 m1 m

NP+NQ=Mgalso NPNQ=53⇒NP=58Mg;NQ=38Mg

Two persons $P$ and $Q$ of the same height are carrying a uniform beam of length $3 m$ . If $Q$ is at one end, then the distance of $P$ from the other end such that $P$ , $Q$ receive loads in the ratio $5 : 3$ is:
$0.5 m$
$0.6 m$
$0.75 m$
$1 m$

$N_{P} + N_{Q} = M g$
also $\frac{N_{P}}{N_{Q}} = \frac{5}{3}$
$\Rightarrow N_{P} = \frac{5}{8} M g; N_{Q} = \frac{3}{8} M g$