A ray of light is incident normally on one face of a 30o−60o−90o prism of refractive index 53 immersed in water of refractive index 43 as shown.
the exit angle θ2 of the ray is sin−1(58)
the exit angle θ2 of the the ray is sin−1(54√3)
total internal reflection at point P ceases if the refractive index of water is increased to 52√3 by dissolving some substance
Total internal reflection at point P ceases if the refractive index of water is increased to 53 by dissolving some substance.
A
the exit angle θ2 of the the ray is sin−1(54√3)
B
Total internal reflection at point P ceases if the refractive index of water is increased to 53 by dissolving some substance.
C
total internal reflection at point P ceases if the refractive index of water is increased to 52√3 by dissolving some substance
D
the exit angle θ2 of the ray is sin−1(58)
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Solution
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From geometry, we find that θ1=60o and θ=30o
Now snell's law at point Q, 43sinθ2=53sinθ⟹sinθ2=58
Also, for total internal reflection to be ceased at point P, then θ′ must be equal to 90o.
Now let new refractive index of water be 52√3, snell's law at point P 53sinθ1=52√3sinθ′
As θ1=60o⟹sinθ′=1⟹θ′=90o
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