The capacitance of a parallel plate condenser is C1(fig. a). A dielectric of dielectric constant ‘K’ is inserted as shown in figure ‘b’ and ‘c’. If C2 and C3 are the capacitances in figures ‘b’ and ‘c’ then :
Both C2 and C3>C1
C3>C1 and C2>C1
Both C2 and C3< C1
C1=C2=C3
A
C3>C1 and C2>C1
B
Both C2 and C3< C1
C
Both C2 and C3>C1
D
C1=C2=C3
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Solution
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We know that capacitance is given by
C1=ε0Ad. b) In C2kε0A2dandεoA2d are in series ⇒1C2=dkεA2+d2ε0A=d2ε0A(1k+1) ⇒C2=ε0Ad(2k1+k) we know k>1 ∴2k1+k>1. ∴C2>C1.
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