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Standard VII
Mathematics
Integers
Question
The largest 3-digit number divisible by 19 is
998
988
999
969
A
998
B
999
C
988
D
969
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Solution
Verified by Toppr
First, divide 999 by 19
999÷19
Q=52 R=11
Now subtract the remainder from 999
999-11
=988
=> 988 is the largest 3 digit number which is exactly divisible by 19
So option A is the correct answer.
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