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Standard XII
Mathematics
Right Hand Limit
Question
the value of
x
l
i
m
−
−
→
0
sin
x
0
x
Open in App
Solution
Verified by Toppr
We have
lim
x
→
0
sin
x
x
=
1
when
x
is in radians
also,
x
∘
=
π
180
x
radians
∴
lim
x
→
0
sin
x
∘
x
=
lim
x
→
0
sin
π
x
180
x
=
lim
x
→
0
sin
(
π
x
180
)
(
π
x
180
)
×
(
180
π
)
⇒
lim
x
→
0
sin
x
∘
x
=
π
180
lim
x
→
0
sin
(
π
x
180
)
(
π
x
180
)
=
π
180
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