Three capacitors 4, 6 and 12 μF are connected in series to a 10 V source. The charge on the middle capacitor is
60 μC
10 μC
20 μC
5 μC
A
10 μC
B
5 μC
C
60 μC
D
20 μC
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Solution
Verified by Toppr
1Ceq=14+16+112=3+2+112⇒Ceq=2μFQ=2μF×10=20μC.
Hence,
option (B) is correct answer.
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