Let us calculate field at Q in case the cavity weren't there, since mass is proportional to R3
Gravitational field g0=GM(2343)122=GM32
Also, field due to mass previously in right cavity will be 0 since the point is at its centre.
Gravitational field due to left sphere,
g′=GM(1343)142=GM1024
Thus, actual magnetic field at Q is
g=g0−g′=GM(132−11024)=31GM1024
Answer is option A.
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