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Class 7
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Maths
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Congruence of Triangles
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Easy Questions
Congruence Of Triangles
Maths
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ABC is an isosceles triangle with AB
$=$
AC and D is a point on BC such that
$AD⊥BC$
(Fig. 7.13). To prove that
$∠BAD=∠CAD,$
a student proceeded as follows:
$ΔABD$
and
$ΔACD,$
AB
$=$
AC (Given)
$∠B=∠C$
(because AB
$=$
AC)
and
$∠ADB=∠ADC$
Therefore,
$ΔABD≅ΔACD(AAS)$
So,
$∠BAD=∠CAD(CPCT)$
What is the defect in the above arguments?
A
It is defective to use
$∠ABD=∠ACD$
for proving this result.
B
It is defective to use
$∠ADB=∠ADC$
for proving this result.
C
It is defective to use
$∠BAD=∠DCA$
for proving this result.
D
Cannot be determined
Easy
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>
Given
$ΔOAP≅ΔOBP$
in figure, the criteria by which the triangles are congruent is:
A
$SAS$
B
$SSS$
C
$RHS$
D
$ASA$
Easy
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>
If
$ΔABC≅ΔDEF$
by SSS congruence rule then
A
$AB=EF,BC=FD,CA=DE$
B
$AB=FD,BC=DE,CA=EF$
C
$AB=DE,BC=EF,CA=FD$
D
$AB=DE,BC=EF,∠C=∠F$
Easy
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>
In
$ΔABC$
and
$ΔDEF$
, AB = DF and
$∠A=∠D$
. The two triangles will be congruent by SAS axiom if :
A
BC = EF
B
AC = DE
C
BC = DE
D
AC = EF
Easy
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>
In triangles ABC and DEF, AB
$=$
FD and
$∠A=∠D$
. The two triangles will be congruent by
SAS axiom if :
A
BC
$=$
EF
B
AC
$=$
DE
C
AC
$=$
EF
D
BC
$=$
DE
Easy
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>
In
$ΔABC$
and
$ΔDEF$
,
$AB=FD$
,
$∠A=∠D$
. The two triangles will be congruent by SAS axiom if :
A
$BC=DE$
B
$AC=EF$
C
$BC=EF$
D
$AC=DE$
Easy
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>
In the given figure, If OA=OB,OD=OC, then
$ΔAOD≅ΔBOC$
by congruence rule:
A
SSS
B
ASA
C
SAS
D
RHS
Easy
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>
If
$ΔABC≅ΔDEF$
by SSS congruence rule then :
A
$AB=EF,BC=FD,CA=DE$
B
$AB=FD,BC=DE,CA=EF$
C
$AB=DE,BC=EF,CA=FD$
D
$AB=DE,BC=EF,∠C=∠F$
Easy
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>
In
$△ABCand△PQR,AB=PQ,AC=PRandBC=QR$
, then the two triangles are congruent by which test?
Easy
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>
In the given figure, if
$AB=DC$
,
$∠ABD=∠CDB$
, which congruence rule would you apply to prove
$ΔABD$
$≅ΔCDB$
?
A
SAS
B
ASA
C
RHS
D
SSS
Easy
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>