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Class 7
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Maths
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Congruence of Triangles
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Medium Questions
Congruence Of Triangles
Maths
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Easy Qs
Med Qs
Hard Qs
>
In the above figure, if OA
$=$
OB, OD
$=$
OC then
$ΔAOD≅ΔBOC$
by congruence rule :
A
$SSS$
B
$ASA$
C
$SAS$
D
$RHS$
Medium
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>
State true/false:
If in
$△ABCand△QRP,AB=QR,∠B=∠Rand∠C=∠P.$
Then, by A.S.A criteria,
$△ABC$
and
$△QRP$
are congruent.
A
True
B
False
Medium
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>
If in two triangles
$ΔABC$
and
$ΔPQR$
,
$AB=QR,BC=PR$
and
$CA=PQ,$
then :
A
$ΔABC≅ΔPQR$
B
$ΔCBA≅ΔPRQ$
C
$ΔBAC≅ΔRPQ$
D
$ΔPQR≅ΔBCA$
Medium
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>
In figure, if
$AB=AC$
and
$AP=AQ$
, then by which congruence criterion
$ΔPBC≅ΔQCB$
?
A
$SSS$
B
$ASA$
C
$SAS$
D
$RHS$
Medium
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>
State whether the given statement is true or false:
In
$△ABC$
and
$△DEF,AB=DE,BC=EF$
and
$∠B=∠E$
. The triangles are congruent by
$SSS$
test.
A
True
B
False
Medium
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>
If
$D$
and
$E$
are the mid-points of the sides
$AB$
and
$AC$
respectively of
$△ABC$
.
$DE$
is produced to
$F$
. To prove that
$CF$
is equal and parallel to
$DA$
, we need an additional information which is:
A
$△DAE$
=
$△EFC$
B
$AE=EF$
C
$DE=EF$
D
$△ADE=△ECF$
Medium
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>
$ΔABC$
is congruent of
$ΔDEF$
, if
A
$AB=DE$
,
$AC=6=DF$
,
$∠A=∠D$
B
$AB=DE$
,
$AC=DF$
,
$∠B=∠E$
C
$AB=DE$
,
$AC=DF$
,
$∠C=∠F$
D
$AB=DE$
,
$AC=DF$
,
$∠C=∠F$
Medium
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>
In the given figure,
$AB=AC$
and
$∠DBC=∠ECB=90_{∘}$
, then
$AD=AE$
.
A
True
B
False
Medium
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>
In
$△ABC$
and
$△DEF$
,
$AB=FD$
and
$∠A=∠D.$
The two triangles will be congruent by
$SAS$
axiom, if:
A
$BC=EF$
B
$AC=DE$
C
$AC=EF$
D
$BC=DE$
Medium
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>
In the given figure,
$AB=AC$
and
$∠DBC=∠ECB=90_{∘}$
,then
$BD=CE$
.
A
True
B
False
Medium
View solution
>