The de-Broglie's wavelength of electron present in first Bohr orbit of $H$ atom is?

Q: The de-Broglie's wavelength of electron present in first Bohr orbit of \$H\$ atom is?

First Bohr orbit of 'H' atom has radius \$r=0.529 \: A^o\$Also, the angular momentum is quantized.\$mvr=\dfrac {h}{2 \pi}\$\$2 \pi r=\dfrac {h}{mv} = \lambda\$\$\lambda = 2\pi \times 0.529\overset{o}{A}\$The de Broglie's wavelength of electron present in first Bohr orbit of H atom is \$ 2\pi \times 0.529\overset{o}{A}\$.So, the correct option is \$B\$

Question

Accepted Answer

First Bohr orbit of 'H' atom has radius $r=0.529 \: A^o$Also, the angular momentum is quantized.$mvr=\dfrac {h}{2 \pi}$$2 \pi r=\dfrac {h}{mv} = \lambda$$\lambda = 2\pi \times 0.529\overset{o}{A}$The de Broglie's wavelength of electron present in first Bohr orbit of H atom is $ 2\pi \times 0.529\overset{o}{A}$.So, the correct option is $B$

Dual Nature Of Radiation And Matter

Physics
3308 Views