Electric Charges And Fields

Q: Two point charges A and B, having charges +Q and -Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes

\\(F=\dfrac{KQ^2}{r^2}\\)If 25% of charge of A transferred to B then \\(q_A = Q - \dfrac{Q}{4} = \dfrac{3 Q}{4} \\) and \\(q_B = -Q + \dfrac{Q}{4} = \dfrac{-3Q}{4}\\)\\(F_1 = \dfrac{kq_A q_B}{r^2}\\)\\(F_1 = \dfrac{k \left(\dfrac{3Q}{4} \right)^2}{r^2}\\)\\(F_1 = \dfrac{9}{16} \dfrac{kQ}{r^2}\\)\\(\implies F_1 = \dfrac{9F}{16}\\)

Q: A hollow metal sphere of radius R is uniformly charged. The electric field due to the sphere at a distance r from the centre

Charge Q will be distributed over the surface of hollow metal sphere. (i) For r R (out side)\\(\oint \bar{E}_0 . \overline{dS} = \dfrac{q_{en}}{\varepsilon_0}\\)Here, \\(q_{en} = Q (\because q_{en} = Q)\\)\\(\therefore E_0 4 \pi r^2 = \dfrac{Q}{\varepsilon _0}\\)\\(\therefore E_0 \propto \dfrac{1}{r^2}\\)

Question

Two point charges A and B, having charges +Q and -Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes

Electric Charges And Fields

Physics 27127 Views

Two point charges A and B, having charges +Q and -Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes

A hollow metal sphere of radius R is uniformly charged. The electric field due to the sphere at a distance r from the centre

Physics
27127 Views