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Class 11
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Economics
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Measures of Central Tendency
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Medium Questions
Measures Of Central Tendency
Economics
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Easy Qs
Med Qs
Hard Qs
>
The mean of
$100$
observations is
$50$
. If one of the observations which was
$50$
is replaced by
$150$
, the resulting mean will be :
A
$50.5$
B
$51$
C
$51.5$
D
$52$
Medium
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>
A football player scored the following number of goals in the
$10$
matches:
$1,3,2,5,8,6,1,4,7,9$
Since the number of matches is
$10$
(an even number), therefore, the median
$=25_{th}observation+6_{th}observation $
$=28+6 =7$
Is it the correct answer and why?
A
Correct
B
Incorrect
C
Ambiguous
D
Data insufficient
Medium
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>
If the mean of variate X in distribution
2.6, then the value of k is
Variate X
1
2
3
4
5
Frequency of X
4
5
k
1
2
A
$8$
B
$10$
C
$12$
D
$18$
Medium
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>
If the mean of the observations:
$x,x+3,x+5,x+7,x+10$
is
$9$
, the mean of the last three observations is
A
$1031 $
B
$1032 $
C
$1131 $
D
$1132 $
Medium
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>
The mean of
$25$
observations is
$36$
. Out of these observations if the mean of first
$13$
observations is
$32$
and that of the last
$13$
observations is
$40$
, the
$13$
th observation is :
A
$23$
B
$36$
C
$38$
D
$40$
Medium
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>
The median of the data
$78,56,22,34,45,54,39,68,54,84$
is
A
$45$
B
$49.5$
C
$54$
D
$56$
Medium
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>
A total of
$25$
patients admitted to a hospital are tested for levels of blood sugar
$(mg/dl)$
and the results obtained were as follows:
$87$
$71$
$83$
$67$
$85$
$77$
$69$
$76$
$65$
$85$
$85$
$54$
$70$
$68$
$80$
$73$
$78$
$68$
$85$
$73$
$81$
$78$
$81$
$77$
$75$
Find mean, median and mode
$(mg/dl)$
of the above data.
A
Mean
$=75.64$
, Median
$=77$
, Mode
$=85$
B
Mean
$=75.64$
, Median
$=76$
, Mode
$=81$
C
Mean
$=75.64$
, Median
$=77$
, Mode
$=81$
D
Mean
$=73.64$
, Median
$=76$
, Mode
$=85$
Medium
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>
The points scored by a basket ball team in a series of matches are as follows:
$17,2,7,27,25,5,14,18,10,24,48,10,8,7,10,28$
Find the median and mode for the data.
A
Median
$=12$
, mode
$=10$
B
Median
$=11$
, mode
$=10$
C
Median
$=12$
, mode
$=18$
D
Median
$=10$
, mode
$=18$
Medium
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>
The mean marks (out of
$100$
) of boys and girls in an examination are
$70$
and
$73$
, respectively. If the mean marks of all the students in that examination is
$71$
, find the ratio of the number of boys to the number of girls.
A
$1:1$
B
$2:1$
C
$1:2$
D
$2:3$
Medium
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>
Mean of
$50$
observations was found to be
$80.4$
. But later on, it was discovered that
$96$
was misread as
$69$
at one place. Find the correct mean.
A
$75.9$
B
$8.4$
C
$79$
D
$80.94$
Medium
View solution
>