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Class 11
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Physics
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Motion in a Straight Line
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Medium Questions
Motion In A Straight Line
Physics
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Easy Qs
Med Qs
Hard Qs
>
Two cars are travelling towards each other on a straight road at velocities
1
5
m
/
s
and
1
6
m
/
s
respectively. When they are
1
5
0
m
apart, both the drivers apply the brakes and the cars decelerate at
3
m
/
s
2
and
4
m
/
s
2
until they stop. Separation between the cars when they come to rest is :
A
8
6
.
5
m
B
8
9
.
5
m
C
8
5
.
5
m
D
8
0
.
5
m
Medium
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>
The average velocity of a freely falling body is numerically equal to half of the acceleration due to gravity. The velocity of the body as it reaches the ground is numerically equal to:
A
g
B
2
g
C
2
g
D
2
g
Medium
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>
A body leaving a certain point
O
moves with an acceleration which is constant. At the end of the first second after it left
O
, its velocity is
1
.
5
m
/
sec
. At the end of the sixth second after it left
O
the body stops momentarily and begins to move backwards. The distance traveled by the body before it stops momentarily is
A
9
m
B
1
8
m
C
5
4
m
D
3
6
m
Medium
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>
A driver takes
0
.
2
0
s
to apply the brakes after he sees a need for it. This is called the reaction time of the driver. If he is driving a car at a speed of
5
4
k
m
/
h
and the brakes causes a deceleration of
6
.
0
m
/
s
2
, find the distance traveled by the car after he sees the need to put the brakes on.
A
1
8
.
6
3
m
B
2
0
m
C
2
6
.
8
5
m
D
2
7
.
6
7
m
Medium
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>
A ball dropped from one metre above the top of a window, crosses the window in
t
1
s
. If the same ball is dropped from
2
m
above the top of the same window, time taken by it to cross the window is
t
2
s
. Then
A
t
2
=
t
1
B
t
2
=
2
t
1
C
t
2
>
t
1
D
t
2
<
t
1
Medium
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>
A proton in a uniform electric field moves along a straight line with constant acceleration starting from rest. If it attains a velocity
4
×
1
0
3
k
m
/
s
at a distance of
2
c
m
, the time required to reach the given velocity is :
A
1
0
−
3
s
B
1
0
−
6
s
C
1
0
−
8
s
D
1
0
−
5
s
Medium
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>
From a building two balls A & B are thrown such that A is thrown upwards and B downwards (both vertically with same speed). If
V
A
and
V
B
are their respective velocities on reaching the ground then :
A
V
B
<
V
A
B
V
A
=
V
B
C
V
A
<
V
B
D
Their velocities depends on their masses
Medium
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>
It takes one minute for a passenger standing on an escalator to reach the top. If the escalator does not move it takes him 3 minutes to walk up. How long will it take for the passenger to arrive at the top if he walks up the moving escalator?
A
3
0
s
e
c
B
4
5
s
e
c
C
4
0
s
e
c
D
3
5
s
e
c
Medium
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>
The average velocity of a body moving with uniform acceleration after travelling a distance of
3
.
0
6
m
is
0
.
3
4
m
/
s
. The change in velocity of the body is
0
.
1
8
m
/
s
. During this time, its acceleration is
A
0
.
0
1
m
/
s
2
B
0
.
0
2
m
/
s
2
C
0
.
0
3
m
/
s
2
D
0
.
0
4
m
/
s
2
Medium
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>
A body travels
2
0
0
m
in the first two second and
2
2
0
m
in the next four second. The velocity at the end of the seventh second from the start will be
A
10
m
s
−
1
B
15
m
s
−
1
C
220
m
s
−
1
D
5
m
s
−
1
Medium
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>