Oscillations

Q: A spring of force constant \$k\$ is cut into lengths of ratio \$1 : 2 : 3\$. They are connected in series and the new force constant is \$k'\$. Then they are connected in parallel and force constant is \$k''\$. Then \$k': k'' \$ is:

spring in series \$\dfrac{1}{k'}=\dfrac{1}{k}+\dfrac{1}{2k}+\dfrac{1}{3k}\rightarrow k'=\dfrac{6k}{11}\$\$k"=k+2k+5k=6k\$\$\dfrac{k'}{k^"}=\dfrac{\dfrac{6k}{11}}{6k}\$ = \$\dfrac{1}{11}\$

Question

A spring of force constant $k$ is cut into lengths of ratio $1 : 2 : 3$ . They are connected in series and the new force constant is $k^{'}$ . Then they are connected in parallel and force constant is $k^{''}$ . Then $k^{'} : k^{''}$ is:

Oscillations

Physics 7363 Views

A spring of force constant k is cut into lengths of ratio 1:2:3. They are connected in series and the new force constant is k′. Then they are connected in parallel and force constant is k′′. Then k′:k′′ is:

Physics
7363 Views

A spring of force constant $k$ is cut into lengths of ratio $1 : 2 : 3$ . They are connected in series and the new force constant is $k^{'}$ . Then they are connected in parallel and force constant is $k^{''}$ . Then $k^{'} : k^{''}$ is: